[dcphp-dev] Re: Repeating pattern incongruent to any calendar increment

Andrew,

I'll tinker with Unix Time. I'll have to account for the server timezone, then reduce it to a date without time, to prevent 00:01 to 23:59 from being counted as a full day (and thus two dates).

Ed,

The trouble is, I should be able to query any specific date in time and know what static value is set for that date. That requires a static pairing of X date = Y value to start with. Today +/- 70 tells me the date, but without knowing what today's value is I can't calculate the value of the +/- 70 date. When I say value, imagine:

09-01-2013 = A

09-02-2013 = B

09-03-2013 = C

09-04-2013 = A

09-05-2013 = B

09-06-2013 = C

Now find out what letter (A/B/C) 05-21-2075 is. If I know any one of those six dates and their value, I can figure it out. What I'm trying to avoid is hardcoding that pairing and in 2075 still calculating from 2013 as a jump-off point.

I'm doing that now, and it works. I just figured the equivalent of 2013 AD in days would skip the first half of the logic:

$pattern = array();

$i=1;

while($i <= 70){

$pattern[$i] = $i. "val";

$i++;

} //echo "<pre>"; print_r($pattern); echo "</pre>";

$reference_date = date_create('2013-09-01'); //any date the pattern begins on; array key 1

$today = date_create(); //echo " [" .date_format($today, "Y-d-m"). "] ";

$days_ago = date_diff($reference_date, $today); //echo " [" .$days_ago->format('%a'). "] ";

$remainder = (float)($days_ago->format('%a')/70);

$remainder = ($remainder - (int)$remainder)*70 +1; //echo $remainder;

echo $pattern[$remainder]; // today's value

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